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Author Topic: found some hybrids.....  (Read 1937 times)
portal_reptiles
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« on: January 16, 2008, 08:28:07 PM »

I found someone that has two crested X chahoua hybrids, one of them is missing his tail..my chance to see if the hybrid will re-grow its tail like a chahoua ...i will post pics next week when they come in
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RAP66
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« Reply #1 on: January 17, 2008, 06:29:30 AM »

Pls post pix, I've been hearing alot about these, and I'm curious on how they look.
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BrianLorys
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« Reply #2 on: January 17, 2008, 02:20:50 PM »

my chance to see if the hybrid will re-grow its tail like a chahoua

That is actually very interesting.

(Disclaimer-- I know nothing about gecko genetics, therefore, this is all a guess to me from what i do know.)

My thoughts would be that all hybrids are different, because when the cellls perform meiosis, the chromosomes are randomly seperated. So lets say the code for no re-growth was tt, and the code for regrowth was TT, and partial was Tt. Than it would be possible for the trait to vary every hatchling. The crestie would obviously have to give a "t", and if the chewie can actually, infact, re-grow his/her tail, they would have to give a "T", leaving with partial regeneration. If chewies can only make a partial regeneration, than they can either give a "T" or a "t" so its a 50/50 chance of partial/no regrowth.

Sorry if that sounded wierd, i confused my self  Huh Cool
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honuman
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« Reply #3 on: January 17, 2008, 03:16:46 PM »


My thoughts would be that all hybrids are different, because when the cellls perform meiosis, the chromosomes are randomly seperated. So lets say the code for no re-growth was tt, and the code for regrowth was TT, and partial was Tt. Than it would be possible for the trait to vary every hatchling. The crestie would obviously have to give a "t", and if the chewie can actually, infact, re-grow his/her tail, they would have to give a "T", leaving with partial regeneration. If chewies can only make a partial regeneration, than they can either give a "T" or a "t" so its a 50/50 chance of partial/no regrowth.

Sorry if that sounded wierd, i confused my self  Huh Cool


Brian it would depend on the how the gene works.  The inhibitor for regrowth might actually be  recessive or vise versa. You would need to determine how the factor that prevents tail regrowth works OR  it may be completely different than the one that allows for tail regeneration.
So the hybrid may only carry that factor. You would first have to see if the tail regenerates or not in a large cross section of F1 hybrids.  I suspect the opposite of what you say would be the case.  100% of the animals will either regenerate their tails or else not regenerate their tails in the F1 batch.  Hmmmm now this is getting confusing Huh
« Last Edit: January 17, 2008, 05:16:51 PM by honuman » Logged

Steve

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BrianLorys
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« Reply #4 on: January 17, 2008, 04:39:48 PM »

I presumed it would be recissive (tail regrowth) since all the other Rhacs seem to be able to do so. Huh I dont know...we learned about this in school a few days ago so i felt all high and mighty  Cool Anyway...i have seen F1, F2, F3, and so on all over, but never was really sure what it meant. Im guessing F1 is like the babies from the original parents, F2 is the babies babies..
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« Reply #5 on: January 17, 2008, 04:49:43 PM »

Anyway...i have seen F1, F2, F3, and so on all over, but never was really sure what it meant. Im guessing F1 is like the babies from the original parents, F2 is the babies babies..

Genetics is some tricky stuff.  Not just about dominant and recessive.  Also sex linked genes and whole host of other things.

You're right on.  F1 would be first generation and so on.
« Last Edit: January 17, 2008, 05:14:35 PM by honuman » Logged

Steve

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portal_reptiles
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« Reply #6 on: January 17, 2008, 07:10:52 PM »

hey i dont know?Huh if he will or not, i will take pics and measureany growth...i keep you all up to date...i dont know that anyone who has a hybrid has lost a tail....so it might be one of the first to see if the chahoua passed this on to it offspirng or not...that would be cool...
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BrianLorys
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« Reply #7 on: January 17, 2008, 08:27:28 PM »

The point i was *trying* to make was that depending on which sperm gets to the egg, it *may* vary. But, if you dont know for sure which is dominant and recessive, than you cant tell for sure.

I would love to see some pics when you get them...and if the tail is regenerated
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« Reply #8 on: January 17, 2008, 09:42:09 PM »

will do..
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« Reply #9 on: January 17, 2008, 09:59:38 PM »

I presumed it would be recissive (tail regrowth) since all the other Rhacs seem to be able to do so. Huh

5 fingers on each hand in humans is recessive Wink
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« Reply #10 on: January 18, 2008, 06:05:42 AM »

I presumed it would be recissive (tail regrowth) since all the other Rhacs seem to be able to do so. Huh

5 fingers on each hand in humans is recessive Wink
brian...are you talking about that it is recessive in all other rhacs other then crested's???...then i think both are right....a person haveing 5 fingers...which is normal....or a chahoua and all the other rhacs. haveing a tail that will regrow. i think it would be recessive to them but might not be in the hybrid becuase the crested's might not have that gene( or dont have the recessive gene for this)...both parents need the gene in order for that trait i think....some of my friends that are in to gene type stuff said we should look into what Gregor Mendel has done with genes and i guess he writes about hybridization...dose anyone know about his work???
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Salzy
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« Reply #11 on: January 18, 2008, 06:33:29 AM »

Gregor Mendel worked mostly with plants and cross-pollination to create hybrids. It was a much quicker method to get a basic study on genetics. Since his time though we have learned a heck of a lot more, but still use his experiments for a base. I don't think it will work the same for chahouas, since genetics is very tricky and nobody really knows about the genetics of Rhacs yet.
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Kyle J. Salzmann

Rhacodactylus: R.auriculatus R.chahoua, R.ciliatus, R.sarasinorum
Uroplatus: U.phantasticus, U.sikorae sikorae, U.sikorae sameti
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« Reply #12 on: January 18, 2008, 11:47:52 AM »

Gregor Mendel worked mostly with plants and cross-pollination to create hybrids. It was a much quicker method to get a basic study on genetics. Since his time though we have learned a heck of a lot more, but still use his experiments for a base. I don't think it will work the same for chahouas, since genetics is very tricky and nobody really knows about the genetics of Rhacs yet.

I agree with Kyle. The gene that controls regeneration and the one that inhibits it could be two completely different things.  Example.  A friend of mine gave me a culture of flightless fruitflies.  He combined Melonastar (sp?) and Heidii (again forgive the spelling)  in this culture. both were flightless yet when they hybridized I got a culture of fully flight capable fruitflies (that wasn't fun) Undecided

Point is both groups of purebred animals had the recessive trait for flightlessness.  Yet a different gene must control that in each of the species because the hybrid's where all flighted.
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Steve

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« Reply #13 on: January 18, 2008, 06:27:04 PM »

yea, i know he worked with plants...but we(people) use the same lay out that he did for our genes, i know a teacher at OSU, i will try to talk to him about this....see if he can give us anything...
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Salzy
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« Reply #14 on: January 18, 2008, 10:34:37 PM »

Mendel's experiments were about as simple as they could be. It turns out that he even got results that he didn't expect. You have to factor in that in most higher organisms, the genes for certain traits can be located at different loci, or even multiple loci in the DNA sequence. One slight change in a base pair could throw off that trait, and it would be recessive. It is far more advanced in the gecko's genome, and without sequencing the DNA of crested geckos, chahouas, AND the hybrids, there is no saying what is what.
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Kyle J. Salzmann

Rhacodactylus: R.auriculatus R.chahoua, R.ciliatus, R.sarasinorum
Uroplatus: U.phantasticus, U.sikorae sikorae, U.sikorae sameti
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